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ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a
Let's first rewrite the given equation in standard form.
Having rewritten the equation, we can identify the values of a, b, and c. - 4x^2+12=- 6x-8 ⇔ - 4x^2+ 6x+ 20=0 Now, let's evaluate the discriminant.
Substitute values
Calculate power
- a(- b)=a* b
Multiply
Add terms
The discriminant is 356.
x=- b±sqrt(b^2-4 a c)/2 a
Substitute values
a(- b)=- a * b
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out - 2
- a/- b=a/b
Cancel out common factors
Using the Quadratic Formula, we found that the solutions of the given equation are x= 3∓sqrt(89)4.