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McGraw Hill Integrated II, 2012 View details

3. The Quadratic Formula and the Discriminant

Finish the assignment

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Exercise 51 Page 197

Mark the segments with known length on the figure.

112.5in^2

Practice makes perfect

Let's mark the segments with known length on the figure. Since P is the center of the circle and both A and B are on the circle, PA and PB are both equal to the given radius of the circle.

To find the area of △ APB, we also use that this is a right triangle, which is given on the figure. The area of a right triangle is half the product of the measure of its legs.

1/2* PA* PB

SubstituteII

PA= 15, PB= 15

1/2( 15)( 15)

Multiply

112.5

The area of △ APB is 112.5 square inches.