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ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a
Let's first rewrite the given equation in standard form.
Having rewritten the equation, we can identify the values of a, b, and c. 4x-3=- 12x^2 ⇔ 12x^2+ 4x+( - 3)=0 Now, let's evaluate the discriminant.
Substitute values
Calculate power
Multiply
- a(- b)=a* b
Add terms
The discriminant is 160.
x=- b±sqrt(b^2-4 a c)/2 a
Substitute values
Multiply
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out 4
Cancel out common factors
Using the Quadratic Formula, we found that the solutions of the given equation are x= - 1±sqrt(10)6.