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ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a
Let's first rewrite the given equation in standard form.
Having rewritten the equation, we can identify the values of a, b, and c. 8x^2=- 2x+1 ⇔ 8x^2+ 2x+( - 1)=0 Now, let's evaluate the discriminant.
Substitute values
Calculate power
Multiply
- a(- b)=a* b
Add terms
The discriminant is 36.
x=- b±sqrt(b^2-4 a c)/2 a
Recall that we have already identified the values of a, b, and c in Part A, as well as the discriminant, b^2-4ac.
The solutions for this equation are x= - 2± 616. Let's separate them into the positive and negative cases.
| x=- 2± 6/16 | |
|---|---|
| x_1=- 2+6/16 | x_2=- 2-6/16 |
| x_1=4/16 | x_2=- 8/16 |
| x_1=1/4 | x_2=-1/2 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1= 14 and x_2=- 12.