McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
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Exercise 4 Page 194

Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.

(- 1+ sqrt(5)/3, - 1- sqrt(5)/3)

Practice makes perfect

We will use the Quadratic Formula to solve the given quadratic equation. ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 aWe first need to identify the values of a, b, and c. 9x^2+6x-4=0 ⇔ 9x^2+ 6x+( - 4)=0 We see that a= 9, b= 6, and c= - 4. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- 6±sqrt(6^2-4( 9)( - 4))/2( 9)
â–¼
Solve for x and Simplify
x=- 6±sqrt(36-4(9)(- 4))/2(9)
x=- 6±sqrt(36-36(- 4))/18
x=- 6±sqrt(36+144)/18
x=- 6±sqrt(180)/18
x=- 6±sqrt(36* 5)/18
x=- 6± sqrt(36)* sqrt(5)/18
x=- 6± 6 sqrt(5)/18
x=6(- 1± sqrt(5))/18
x=- 1± sqrt(5)/3

Using the Quadratic Formula, we found that the solutions of the given equation are x= - 1± sqrt(5)3. Therefore, the solutions are x_1= - 1+ sqrt(5)3 and x_2= - 1- sqrt(5)3.