McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
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Exercise 2 Page 194

Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.

(- 4+sqrt(11), - 4-sqrt(11))

Practice makes perfect

We will use the Quadratic Formula to solve the given quadratic equation. ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 aWe first need to identify the values of a, b, and c. x^2+8x+5=0 ⇔ 1x^2+ 8x+ 5=0 We see that a= 1, b= 8, and c= 5. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- 8±sqrt(8^2-4( 1)( 5))/2( 1)
â–¼
Solve for x and Simplify
x=- 8±sqrt(64-4(1)(5))/2(1)
x=- 8±sqrt(64-20)/2
x=- 8±sqrt(44)/2
x=- 8±sqrt(4* 11)/2
x=- 8± sqrt(4)* sqrt(11)/2
x=- 8± 2 sqrt(11)/2
x=2(- 4± sqrt(11))/2
x=- 4± sqrt(11)

Using the Quadratic Formula, we found that the solutions of the given equation are x=- 4± sqrt(11). Therefore, the solutions are x_1=- 4+sqrt(11) and x_2=- 4-sqrt(11).