McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
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Exercise 7 Page 194

Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.

(2+ 2sqrt(7)/3, 2- 2sqrt(7)/3)

Practice makes perfect

We will use the Quadratic Formula to solve the given quadratic equation. ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.

- 3x^2+4x=- 8
- 3x^2+4x+8=0

Now, we can identify the values of a, b, and c. - 3x^2+4x+8=0 ⇔ - 3x^2+ 4x+ 8=0 We see that a= - 3, b= 4, and c= 8. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- 4±sqrt(4^2-4( - 3)( 8))/2( - 3)
â–¼
Solve for x and Simplify
x=- 4±sqrt(16-4(- 3)(8))/2(- 3)
x=- 4±sqrt(16+12(8))/2(- 3)
x=- 4±sqrt(16+96)/2(- 3)
x=- 4±sqrt(112)/2(- 3)
x=- 4±sqrt(16* 7)/2(- 3)
x=- 4± sqrt(16)* sqrt(7)/2(- 3)
x=- 4± 4 sqrt(7)/2(- 3)
x=2(- 2± 2sqrt(7))/2(- 3)
x=- 2± 2sqrt(7)/- 3
x=- (2∓ 2sqrt(7))/- 3
x=2∓ 2sqrt(7)/3

Using the Quadratic Formula, we found that the solutions of the given equation are x= 2∓ 2sqrt(7)3. Therefore, the solutions are x_1= 2-2sqrt(7)3 and x_2= 2+2sqrt(7)3.