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Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
(2+ 2sqrt(7)/3, 2- 2sqrt(7)/3)
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.
Now, we can identify the values of a, b, and c. - 3x^2+4x+8=0 ⇔ - 3x^2+ 4x+ 8=0 We see that a= - 3, b= 4, and c= 8. Let's substitute these values into the Quadratic Formula.
Substitute values
Calculate power
- a(- b)=a* b
Multiply
Add terms
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out 2
Cancel out common factors
Factor out - 1
- a/- b=a/b
Using the Quadratic Formula, we found that the solutions of the given equation are x= 2∓ 2sqrt(7)3. Therefore, the solutions are x_1= 2-2sqrt(7)3 and x_2= 2+2sqrt(7)3.