McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
Continue to next subchapter

Exercise 41 Page 196

Practice makes perfect
a Let's extend the table with a column for the value of x, the number of years after 2010.
Year x Deaths per 100 000
2000 0 91.8
2002 2 89.7
2004 4 85.5
2010 10 60.3
2015 15 ?
2017 17 ?

Let's substitute the x-values in the formula given in the question to calculate the missing entries. We start with x=15.

y=- 0.26x^2-0.55x+91.81
y=- 0.26( 15^2)-0.55( 15)+91.81
â–¼
Evaluate right-hand side
y=- 0.26(225)-0.55(15)+91.81
y=- 58.5-8.25+91.81
y=25.06

Let's repeat the same process with x=17.

y=- 0.26x^2-0.55x+91.81
y=- 0.26( 17^2)-0.55( 17)+91.81
â–¼
Evaluate right-hand side
y=- 0.26(289)-0.55(17)+91.81
y=- 75.14-9.35+91.81
y=7.32

Now put these values in the table.

Year x Deaths per 100 000
2015 15 25.06
2017 17 7.32

b We are asked to solve a quadratic equation.

50=-0.26x^2-0.55x+91.81 We will use the Quadratic Formula to find the solutions. 2 &Quadratic equation: && ax^2+ bx+ c=0 &Solutions:&&x=- b±sqrt(b^2-4 a c)/2 aTo identify the coefficients, we need to rearrange our equation.

50=-0.26x^2-0.55x+91.81
0=-0.26x^2-0.55x+91.81- 50
0=-0.26x^2-0.55x+41.81

In this form we can identify the coefficients. - 0.26x^2-55x+41.81= - 0.26x^2+( - 0.55)x+ 41.81 We see that a= - 0.26, b= - 0.55, and c= 41.81. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- ( -0.55)±sqrt(( - 0.55)^2-4( -0.26)( 41.81))/2( -0.26)
â–¼
Simplify right-hand side
x=0.55±sqrt(( - 0.55)^2-4( -0.26)( 41.81))/2( -0.26)
x=0.55±sqrt(0.3025-4( -0.26)( 41.81))/2( -0.26)
x=0.55±sqrt(0.3025-167.24( -0.26))/2( -0.26)
x=0.55±sqrt(0.3025-(-43.4824))/-0.52
x=0.55±sqrt(0.3025+43.4824)/-0.52
x=0.55±sqrt(43.7849)/-0.52

Let's use a calculator to find approximate values of these solutions. 0.55+sqrt(43.7849)/-0.52&≈ -13.78 0.55-sqrt(43.7849)/-0.52&≈ 11.67 Since x represents the number of years after 2000, we need the positive solution. The year in which the number of deaths caused by lung cancer is 50 per 100 000 corresponds to x=11.67.

c To find the year when the death rate is predicted to be 0, we solve a quadratic equation similar to the one we solved in Part B. This time we need to find the x that gives the prediction 0 instead of 50.

- 0.26x^2 - 0.55x+ 91.81=0 We see that a= - 0.26, b= - 0.55, and c= 91.81. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- ( -0.55)±sqrt(( - 0.55)^2-4( -0.26)( 91.81))/2( -0.26)
â–¼
Simplify right-hand side
x=0.55±sqrt(( - 0.55)^2-4( -0.26)( 91.81))/2( -0.26)
x=0.55±sqrt(0.3025-4( -0.26)( 91.81))/2( -0.26)
x=0.55±sqrt(0.3025-367.24( -0.26))/2( -0.26)
x=0.55±sqrt(0.3025-(-95.4824))/-0.52
x=0.55±sqrt(0.3025+95.4824)/-0.52
x=0.55±sqrt(95.7849)/-0.52

Let's use a calculator to find approximate values of these solutions. 0.55+sqrt(95.7849)/-0.52&≈ -19.88 0.55-sqrt(95.7849)/-0.52&≈ 17.76 Since x represents the number of years after 2000, we need the positive solution. The year in which the number of deaths caused by lung cancer is predicted to reduce to 0 corresponds to x=17.76. 2000+17.76=2017.76 According to the quadratic function, the death rate will be 0 in 2017. This is not a reasonable prediction. Even with a cure (which is currently not known), the success rate is unlikely to be 100 %.