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Factor out i.
1/2+i and 1/2-i
We are given a quadratic equation and asked to use the Quadratic Formula to find the solutions.
2
&Quadratic equation: && ax^2+ bx+ c=0
&Solutions:&&x=- b±sqrt(b^2-4 a c)/2 a
Notice that all coefficients of the equation in the question are multiples of i.
Let's factor it out and divide the equation before we use the Quadratic Formula.
Let's use this form to identify the coefficients. 4x^2-4x+5= 4x^2+( - 4)x+ 5 We see that a= 4, b= - 4, and c= 5. Let's substitute these values into the Quadratic Formula.
Substitute values
Notice that sqrt(-64) is not a real number. However, using that i^2=-1, we can replace it with isqrt(64)=8i. Let's make this change and simplify the result.
Rewrite sqrt(-64) as 8i
Write as a sum of fractions
a/b=.a /4./.b /4.
a = 8* a/8
We found the two solutions of the equation. 1/2+i and 1/2-i