McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
Continue to next subchapter

Exercise 44 Page 196

Factor out i.

1/2+i and 1/2-i

Practice makes perfect

We are given a quadratic equation and asked to use the Quadratic Formula to find the solutions. 2 &Quadratic equation: && ax^2+ bx+ c=0 &Solutions:&&x=- b±sqrt(b^2-4 a c)/2 a Notice that all coefficients of the equation in the question are multiples of i. Let's factor it out and divide the equation before we use the Quadratic Formula.

4ix^2-4ix+5i=0
â–¼
Simplify
i(4x^2-4x+5)=0
4x^2-4x+5=0/i
4x^2-4x+5=0

Let's use this form to identify the coefficients. 4x^2-4x+5= 4x^2+( - 4)x+ 5 We see that a= 4, b= - 4, and c= 5. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- ( -4)±sqrt(( - 4)^2-4( 4)( 5))/2( 4)
â–¼
Simplify right-hand side
x=4±sqrt(( - 4)^2-4( 4)( 5))/2( 4)
x=4±sqrt(16-4( 4)( 5))/2( 4)
x=4±sqrt(16-80)/8
x=4±sqrt(-64)/8

Notice that sqrt(-64) is not a real number. However, using that i^2=-1, we can replace it with isqrt(64)=8i. Let's make this change and simplify the result.

x=4±sqrt(-64)/8
x=4± 8i/8
â–¼
Simplify right-hand side
x=4/8±8i/8
x=1/2±8i/8
x=1/2± i

We found the two solutions of the equation. 1/2+i and 1/2-i