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ax^2+bx+c=0 ⇔ x=- b±sqrt(b^2-4ac)/2a
Let's first rewrite the given equation in standard form.
Having rewritten the equation, we can identify the values of a, b, and c. x^2+2x-4=- 9 ⇔ 1x^2+ 2x+ 5=0 Now, let's evaluate the discriminant.
The discriminant is - 16.
x=- b±sqrt(b^2-4 a c)/2 a
Substitute values
a * 1=a
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
sqrt(- 1)= i
Calculate root
Factor out 2
Cancel out common factors
Using the Quadratic Formula, we found that the solutions of the given equation are x=- 1± 2i.