McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
Continue to next subchapter

Exercise 3 Page 194

Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.

(5+sqrt(57)/8, 5-sqrt(57)/8)

Practice makes perfect

We will use the Quadratic Formula to solve the given quadratic equation. ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 aWe first need to identify the values of a, b, and c. 4x^2-5x-2=0 ⇔ 4x^2+( - 5)x+( - 2)=0 We see that a= 4, b= - 5, and c= - 2. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- ( - 5)±sqrt(( - 5)^2-4( 4)( - 2))/2( 4)
â–¼
Solve for x and Simplify
x=5±sqrt((- 5)^2-4(4)(- 2))/2(4)
x=5±sqrt(25-4(4)(- 2))/2(4)
x=5±sqrt(25-16(- 2))/8
x=5±sqrt(25+32)/8
x=5±sqrt(57)/8

Using the Quadratic Formula, we found that the solutions of the given equation are x= 5±sqrt(57)8. Therefore, the solutions are x_1= 5+sqrt(57)8 and x_2= 5-sqrt(57)8.