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Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
- 3± sqrt(15)/2
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.
LHS+12x=RHS+12x
Factor out 2
.LHS /2.=.RHS /2.
Now, we can identify the values of a, b, and c. 2x^2+6x-3=0 ⇔ 2x^2+ 6x+( - 3)=0 We see that a= 2, b= 6, and c= - 3. Let's substitute these values into the Quadratic Formula.
Substitute values
Calculate power
Multiply
- a(- b)=a* b
Add terms
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out 2
Cancel out common factors
Using the Quadratic Formula, we found that the solutions of the given equation are x= - 3± sqrt(15)2. Therefore, the solutions are x_1= - 3+ sqrt(15)2 and x_2= - 3- sqrt(15)2.