McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. The Quadratic Formula and the Discriminant
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Exercise 42 Page 196

Set up and solve a quadratic equation.

36

Practice makes perfect

We are given the formula for the sum of the first n positive integers, and we are asked to find n when this formula gives a sum of 666. 1/2n(n+1)=666 We can solve this quadratic equation in two steps. First let's rearrange it to standard form, then let's use the Quadratic Formula to find the solution.

Rearranging the Equation

1/2n(n+1)=666
n(n+1)=1332
n^2+n=1332
n^2+n-1332=0

Solving the Equation

Once we have the equation in standard form, we can use the Quadratic Formula to solve it. 2 &Quadratic equation: && ax^2+ bx+ c=0 &Solutions:&&x=- b±sqrt(b^2-4 a c)/2 a Let's identify the coefficients in our quadratic expression. n^2+n-1332= 1n^2+ 1n+( - 1332) We see that a= 1, b= 1, and c= -1332. Let's substitute these values into the Quadratic Formula.

n=- b±sqrt(b^2-4ac)/2a
n=- 1±sqrt(1^2-4( 1)( -1332))/2( 1)
â–¼
Simplify right-hand side
n=- 1±sqrt(1-4( 1)( -1332))/2( 1)
n=- 1±sqrt(1-4( -1332))/2
n=- 1±sqrt(1-(-5328))/2
n=- 1±sqrt(1+5328)/2
n=- 1±sqrt(5329)/2
n=-1±73/2

Since we are looking for a positive integer, we only consider the solution with a sum in the numerator. n=-1+73/2=72/2=36 We need to add 36 integers from 1 to 36 to get the sum 666.