Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
(- 3+ sqrt(14), - 3- sqrt(14))
Practice makes perfect
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.
Now, we can identify the values of a, b, and c.
x^2+6x-5=0 ⇔ 1x^2+ 6x+( - 5)=0
We see that a= 1, b= 6, and c= - 5. Let's substitute these values into the Quadratic Formula.
Using the Quadratic Formula, we found that the solutions of the given equation are x=- 3± sqrt(14). Therefore, the solutions are x_1=- 3+ sqrt(14) and x_2=- 3- sqrt(14).
