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Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
- 3± isqrt(71)/8
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.
LHS+17=RHS+17
Factor out 3
.LHS /3.=.RHS /3.
Now, we can identify the values of a, b, and c. 4x^2+ 3x+ 5=0 We see that a= 4, b= 3, and c= 5. Let's substitute these values into the Quadratic Formula.
Substitute values
Calculate power
Multiply
Multiply
Subtract term
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
sqrt(- 1)= i
Using the Quadratic Formula, we found that the solutions of the given equation are x= - 3± isqrt(71)8. Therefore, the solutions are x_1= - 3+ isqrt(71)8 and x_2= - 3- isqrt(71)8.