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Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
(1.5, - 0.2)
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.
Now, we can identify the values of a, b, and c. 10x^2-13x-3=0 ⇕ 10x^2+( - 13)x+( - 3)=0 We see that a= 10, b= - 13, and c= - 3. Let's substitute these values into the Quadratic Formula.
Substitute values
The solutions for this equation are x= 13± 1720. Let's separate them into the positive and negative cases.
| x=13± 17/20 | |
|---|---|
| x_1=13+17/20 | x_2=13-17/20 |
| x_1=30/20 | x_2=- 4/20 |
| x_1=1.5 | x_2=- 0.2 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1=1.5 and x_2=- 0.2.