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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

1. Solving One-Step Equations

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Exercise 48 Page 85

Isolate n on one side of the equation.

-14

Practice makes perfect

To solve the equation, we have to isolate n. Using the Multiplication Property of Equality, we will multiply both sides of the equation by the reciprocal of the coefficient of the variable n. This will eliminate the fraction and isolate n.

- 6=3/7n

LHS * 7/3=RHS* 7/3

- 6 * 7/3=3/7n * 7/3

CommutativePropMult

Commutative Property of Multiplication

- 6 * 7/3=7/3 * 3/7 * n

MultFracByInverse

a/b* b/a=1

- 6 * 7/3=1 * n

Identity Property of Multiplication

- 6 * 7/3=n

Rearrange equation

n=- 6 * 7/3

MoveLeftFacToNum

a*b/c= a* b/c

n=-6 * 7/3

Multiply

n=-42/3

MoveNegNumToFrac

Put minus sign in front of fraction

n=-42/3

Calculate quotient

n=- 14

The solution is n=- 14. Let's test this solution by substituting it into the original equation.

- 6 =3/7n

n= -14

- 6 =3/7 (- 14)

MoveRightFacToNum

a/c* b = a* b/c

- 6? =3(- 14)/7

Multiply

- 6? =- 42/7

Calculate quotient

- 6=- 6 ✓

Since both sides are equal, n=- 14 is the correct solution.

Subchapter links

Lesson Check p.85

Practice and Problem-Solving Exercises p.85-87

Standardized Test Prep p.87

Mixed Review p.87