Exercise 67 Page 86

How can you isolate t on one side?

t=-25

Practice makes perfect

To solve the equation, we have to isolate t on one side. By multiplying both sides of the equation by 10, we can cancel out the denominator and isolate t.

-2 12=t/10

MixedToFrac

a bc=a* c+b/c

-5/2=t/10

MultEqn

LHS * 10=RHS* 10

-5/2*10=t/10*10

FracMultDenomToNumber

a/10* 10 = a

-5/2*10=t

MoveRightFacToNum

a/c* b = a* b/c

-5*10/2=t

MultNegPos

(- a)b = - ab

-50/2=t

CalcQuot

Calculate quotient

-25=t

RearrangeEqn

Rearrange equation

t=-25

Therefore, t=-25 is the solution to the equation. To check that we have the correct solution, we can substitute t=-25 into the original equation and simplify.

-2 12=t/10

MixedToFrac

a bc=a* c+b/c

-5/2=t/10

Substitute

t= -25

-5/2? =-25/10

MoveNegDenomToFrac

Put minus sign in front of fraction

-5/2? =-25/10

ReduceFrac

a/b=.a /5./.b /5.