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Pearson Algebra 1 Common Core, 2011 View details

1. Solving One-Step Equations

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Exercise 40 Page 85

How can you isolate m on one side?

m=65

Practice makes perfect

To solve the equation we have to isolate m on one side. By multiplying both sides of the equation by -5, we can eliminate the denominator and isolate m.

-13=m/-5

MultEqn

LHS * -5=RHS* -5

-13(-5)=m/-5(-5)

FracMultDenomToNumber

a/-5* -5 = a

-13(-5)=m

MultNegNegOnePar

- a(- b)=a* b

65=m

RearrangeEqn

Rearrange equation

m=65

Therefore, m=65 is the solution to the equation. To check that we have the correct solution, we can substitute m=65 into the original equation and evaluate.

-13=m/-5

Substitute

m= 65

-13? =65/-5

CalcQuot

Calculate quotient

-13=-13

Since the left-hand side and right-hand side are equal, m=65 is the correct solution.

Subchapter links

Lesson Check p.85

Practice and Problem-Solving Exercises p.85-87

Standardized Test Prep p.87

Mixed Review p.87

Exercise 40 Page 85

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