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Pearson Algebra 1 Common Core, 2011 View details

1. Solving One-Step Equations

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Exercise 87 Page 87

Pay close attention to the order of operations.

25/36

Practice makes perfect

According to the order of operations, expressions inside parentheses are evaluated first, while addition and subtraction are evaluated last. For the given expression, this means evaluating the expression inside the parentheses completely before evaluating the power. (1/2+1/3)^2

When adding fractions they must have the same denominator. Since 2*3=6, we can create the same denominator by multiplying the numerator and denominator in the first fraction by 3 and by multiplying the numerator and denominator in the second fraction by 2. 1 * 3/2 * 3+1 * 2/3* 2 ⇔ 3/6+2/6 Let's perform the operations.

Operation	Before Simplification	After Simplification
Add fractions	( 3/6+ 2/6)^2	( 3+2/6)^2
Add terms	(3+2/6)^2	(5/6)^2
(a/b)^m=a^m/b^m	(5/6)^2	5^2/6^2
Calculate power	5^2/6^2	25/36

The expression equals 2536.

Alternative Solution

Using a Calculator

We can also evaluate this expression using a calculator. To do so, type it as shown below.

Subchapter links

Lesson Check p.85

Practice and Problem-Solving Exercises p.85-87

Standardized Test Prep p.87

Mixed Review p.87

Exercise 87 Page 87

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