Exercise 25 Page 85

To solve the equation we have to isolate j on one side. By adding 3 to both sides, we can cancel out the - 3 and isolate j.

j-3=-7

AddEqn

LHS+3=RHS+3

j-3+3=-7+3

AddTerms

Add terms

j=-4

Therefore, j=-4 is the solution to the equation. To check that we have the correct solution, we can substitute j=-4 into the original equation and simplify.

j-3=-7

Substitute

j= -4

-4-3? =-7

SubTerm

Subtract term

-7=-7

Since the left-hand side and right-hand side are equal, j=-4 is the correct solution.