body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

1. Solving One-Step Equations

Continue to next subchapter

Exercise 68 Page 86

How can we isolate b on the left-hand side?

b=1.7

Practice makes perfect

To solve the equation, we have to isolate b on one side of the equation. By dividing both sides of the equation by 5, we can remove the coefficient from b.

5b=8.5

.LHS /5.=.RHS /5.

5b/5=8.5/5

FracMultDenomToNumber

a/5* 5 = a

b=8.5/5

Calculate quotient

b=1.7

To check that we have the correct solution, we can substitute b=1.7 into the original equation.

5b=8.5

b= 1.7

5* 1.7? =8.5

Multiply

8.5=8.5

Since both sides are equal, we can conclude that b=1.7 is the correct solution.

Subchapter links

Lesson Check p.85

Practice and Problem-Solving Exercises p.85-87

Standardized Test Prep p.87

Mixed Review p.87