Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
9. Percents
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Exercise 59 Page 143

Assume that the minimum number of miles you travel is 18 mile. How can you treat the $1.75 charge?

Equation: c=1.75+2.4(m-1/8)
Distance Traveled: 25/8mi

Practice makes perfect

First we will write the equation and then determine the number of miles we traveled if a ride cost $7.75.

Writing an Equation

Let's assume that the minimum number of miles we have to pay for is 18 mile. This means that $1.75 can be treated as a fixed cost F. F= 1.75

If we pay more than F, the cost will depend on the number of miles we travel above the first 18 mile. The taxi charges $0.30 for each additional 18 mile However, since one-eighths of one mile is an awkward unit to work with, we will convert this to a per-mile cost by multiplying 0.3 by 8. 1mile charge: $0.30* 8=$2.4 This means that for each additional 1 mile, the taxi charges $ 2.4. We can now create an algebraic expression that describes the variable cost V in terms of the number of miles m. Note that the first 18 mile we travel is payed for by the fixed cost. V = 2.4 (m-1/8) Now we can write the equation for the cost c which is the sum of the fixed and variable cost. c= F+ V ⇓ c= 1.75+ 2.4 (m-1/8)

Finding the Number of Miles

To find how many miles we traveled if a ride costs $7.75, we substitute c= 7.75 in the equation and solve for m.
c=1.75+2.4*(m-1/8)
7.75=1.75+2.4*(m-1/8)
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Solve for m
6=2.4*(m-1/8)
2.5=m-1/8
2.5+1/8=m
20/8+1/8=m
21/8=m
m=21/8
The number of miles traveled was 218, which is equivalent to 2 58 mi.