A'(2,120^(∘))
A''(2,210^(∘))
A'''(2,300^(∘)) Explanation: See solution.
Practice makes perfect
To rotate the point by a certain number of degrees, we add this number to m∠XOA. Since m∠XOA=30^(∘) the new angles becomes
30^(∘)+90^(∘)=120^(∘)
30^(∘)+180^(∘)=210^(∘)
30^(∘)+270^(∘)=300^(∘)Let's illustrate the image of A', A'', and A''',
The only thing that's changes is the angle so the new points can be written as:
A'&(2,120^(∘))
A''&(2,210^(∘))
A'''&(2,300^(∘))
