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| 15 Theory slides |
| 10 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Identifying whether one figure is the image of another figure under rotation can be difficult. A key aspect to observe is whether the center of rotation is the same distance from an image as it is from its preimage.
A rotation is a transformation in which a figure is turned about a fixed point P. The number of degrees the figure rotates α∘ is the angle of rotation. The fixed point P is called the center of rotation. Rotations map every point A in the plane to its image A′ such that one of the following statements is satisfied.
Remember, after performing a rotation, the preimage and the image of a point are the same distance from the center of rotation. The angle of rotation is formed by a preimage, the center of rotation, and the corresponding image.
Rotations can be performed by hand with the help of a straightedge, a compass, and a protractor.
To rotate point A about point P by an angle of 130∘ measured counterclockwise, follow these five steps.
Place the center of the protractor on P and align it with PA.
The protractor is placed as illustrated above when the rotation is counterclockwise. If the rotation has to be done clockwise, the protractor needs to be placed as follows.
Locate the corresponding measure on the protractor and make a small mark. In this case, the mark will be made at 130∘.
Notice that this method of construction has also confirmed that PA is congruent to PA′.
On a geometry test, Ignacio was asked to perform a 70∘ counterclockwise rotation to △ABC about point P.
Draw △ABC and its image under this rotation.
Finally, the image of △ABC under the given rotation is the triangle formed by A′, B′, and C′.
Given a figure and its image under a rotation, the following theorem can be used to find the center of rotation.
If a point is equidistant from the endpoints of a line segment, then it lies on the perpendicular bisector of the segment. |
With this theorem in mind, consider the following example. In the diagram, quadrilateral A′B′C′D′ is the image of ABCD under a certain rotation.
Find the center and angle of rotation.
Angle of Rotation: 120∘ clockwise or 240∘ counterclockwise.
Graph:
Remember that the center of rotation is equidistant from the preimage and the image of each vertex. Use the Converse Perpendicular Bisector Theorem. The center is the intersection point between two perpendicular bisectors.
The first step is to find the center of rotation. Remember, by definition, a point and its image under a rotation are the same distance from the center.
The center of rotation is equidistant from a point and its image.
Therefore, by the Converse of the Perpendicular Bisector Theorem, the center lies on the perpendicular bisector of AA′, for instance. Then, with the aid of a compass and a straightedge, start by constructing the perpendicular bisector of this segment.
To determine the center's exact position, draw a second segment joining a vertex and its image, for example, DD′. Then, draw the perpendicular bisector of this segment. The intersection between both perpendicular bisectors is the center of rotation.
Notice that drawing only two perpendicular bisectors is enough to find the center of rotation because all will intersect at the same point. Since the sense of rotation was not specified, both measures will be found using a protractor.
The angle of rotation is either 240∘ counterclockwise or 120∘ clockwise.
If the point is not placed close enough to the center of rotation, when the Check Answer
button is pushed, a red area is highlighted indicating the region where the center of rotation is located.
Recall that rotations are transformations and that transformations can be composed. Therefore, it is possible to have a composition of two or more rotations. On a geometry exercise, the following two rotations are given.
LaShay has to perform both rotations to △ABC, one after the other, but the book does not indicate the composition's order.
In real life, there are plenty of situations where rotations can be appreciated. For instance, take a look at a door.
Triangle Q has been rotated 100∘ counterclockwise about point P. Which of the four outlined triangles represents the correct rotation? Find the answer by performing the rotation.
Let's remove the coordinate plane for now and only show how we rotate one of the vertices.
To rotate a point we need a compass, a protractor, and a straightedge. There are 4 steps to performing a rotation.
Now that we know how to rotate a point, we will do this for all vertices of △ Q. Let's remove the four outlined triangles when we perform the rotation.
If we add the four alternatives to the diagram, we see that C represents the correct rotation.
The current direction of the windsock is northeast. Let's use a coordinate plane to represent the windsock from above. Then, we will rotate it 270^(∘) counterclockwise.
After a 270^(∘) rotation, the windsock points southeast.
What are the coordinates of B after a 90∘ rotation counterclockwise about the origin?
What are the coordinates of D after a 180∘ rotation counterclockwise about the origin?
What are the coordinates of Q after a 270∘ rotation counterclockwise about the origin?
When we rotate a shape by 90^(∘) counterclockwise about the origin, the coordinates of the vertices change in the following way. Rotation of90^(∘) Counterclockwise About the Origin (x,y) → (- y, x) Using this rule, we can find the x- and y-coordinates of the image's vertices.
△ ABC | (x,y) | (- y, x) |
---|---|---|
A | (- 3,2) | (-2,-3) |
B | (2,4) | (- 4,2) |
C | (3,1) | (- 1,3) |
Knowing the vertices of △ A'B'C', we can draw the image.
The coordinates of B' are (- 4,2).
When a shape is rotated by 180^(∘) counterclockwise about the origin, the shape's vertices will change. Rotation of180^(∘) Counterclockwise About the Origin (x,y) → (- x, - y) Let's use the rule to find the x- and y-coordinates of the image's vertices.
△ DEF | (x,y) | (- x,- y) |
---|---|---|
D | (- 3,- 1) | (3,1) |
E | (- 1,2) | (1,- 2) |
F | (4,- 2) | (- 4,2) |
Knowing the vertices of △ D'E'F', we can draw the image.
The coordinates of D' are (3,1).
When we rotate a shape by 270^(∘) counterclockwise about the origin, the vertices of this shape will change in the following way. Rotation of270^(∘) Counterclockwise About the Origin (x,y) → (y, - x) Using this rule, we can determine the x- and y-coordinates of the rotated figure.
QRST | (a,b) | (b,- a) |
---|---|---|
Q | (- 6,- 3) | (- 3,6) |
R | (- 5,0) | (0,5) |
S | (- 3,0) | (0,3) |
T | (- 1,- 3) | (- 3,1) |
Knowing the vertices of Q'R'S'T', we can draw its image.
The coordinates of Q' are (-3,6).
The four triangles, A through D, are all rotations of Q. Which one(s) can be described by a rotation of Q about point P?
To determine if P is the center of rotation, we can measure the distance from the vertex of a polygon to P by using a compass. Then measure the distance from P to a corresponding vertex on an image. If P is the center of rotation, these distances are equal. Let's choose an arbitrary vertex on Q and measure the length to P.
Without changing the compass settings, place the compass along the segment that connects P and the corresponding vertex on one of the rotated triangles. If the pen on the compass can be drawn across the corresponding vertex, we know that the distances are equal. Let's try this with A.
The distance from corresponding vertices to P are the same. Let's do the same thing for the rest of the images.
Now we can discard B and C as rotations about P. However, to be sure that A and C are, in fact, rotations about P, we have to test a second pair of corresponding vertices.
They correspond! Now we can conclude that A and C are, in fact, rotations of Q about P.
Find the angle of rotation counterclockwise around C that maps A onto A′.
To find the angle of rotation, we need to connect two corresponding vertices on the image and preimage. We are free to pick any pair of vertices we want, as long as they are corresponding.
Next, we want to measure the angle of rotation using a protractor. Place the protractor alongside the segment we just drew and measure the angle that it creates about C counterclockwise.
The angle of rotation is 180^(∘).
As in part A, we need to find two corresponding vertices and measure the angle of rotation counterclockwise with respect to the center of rotation. We may pick any pair of corresponding vertices we want. However, we prefer to use a pair of corresponding points that are also lattice points.
As in part A, we will use a protractor to measure the angle of rotation.
The angle of rotation is 90^(∘).
Like in part C, we will draw segments between two corresponding vertices. Since all of them are on lattice points we will choose a pair arbitrarily.
Notice that a rotation counterclockwise of A to A' requires an angle that is greater than 180^(∘). But a protractor can only measure angles up to 180^(∘). However, we can still use the protractor by measuring the conjugate angle and subtract this measure from 360^(∘).
The conjugate angle is 90^(∘). If we subtract this measure from 360^(∘) we can determine the angle of rotation. 360^(∘)-90^(∘)=270^(∘)
Triangle A′B′C′ is a rotation of triangle ABC about some center of rotation P.
The coordinates of the center of rotation P can be found by following these steps.
Let's find the center of rotation of the given triangles.
Let's first connect two pairs of corresponding vertices. We will choose to draw AA' and BB'.
Next, let's find the perpendicular bisector to one of the segments.
There are two steps in constructing a perpendicular bisector. Let's remove the coordinate plane for now, leaving only the triangles behind. We will also remove one of the segments between corresponding vertices.
If we draw the perpendicular bisector of the second segment, we can locate the center of rotation. The center of rotation is where the perpendicular bisectors intersect.
As we can see, the center of rotation is at P(8,6).