Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. Arithmetic Sequences
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Exercise 59 Page 280

A sequence is arithmetic if the difference between two consecutive terms is constant.

Is the Sequence Arithmetic? Yes.
Explanation: See solution.
Recursive Formula: A(n)=A(n-1)-0.8, A(1)=0.2
Explicit Formula: A(n)=0.2+(n-1)(- 0.8)

Practice makes perfect

When a sequence is arithmetic, the difference between two consecutive terms is constant. Examining our sequence we can see that this is the case. 0.2 +( - 0.8) âź¶ - 0.6 +( - 0.8) âź¶ - 1.4 +( - 0.8) âź¶ - 2.2 +( - 0.8) âź¶ ... Since the difference between consecutive terms is constant and equal to - 0.8, we have an arithmetic sequence with common difference - 0.8. We will use this information to write both the recursive and the explicit formula.

Recursive Formula

Let's recall the general form of the recursive formula for an arithmetic sequence. A(n)=A(n-1)+d In the above formula, n is the term number and d the common difference. By substituting d= - 0.8 into this formula, we can create our recursive rule.
A(n)=A(n-1)+d
A(n)=A(n-1)+( -0.8)
A(n)=A(n-1)-0.8
To complete the recursive formula, we need to state the value of the first term, which in this case is A(1)= 0.2. Recursive Formula A(n)=A(n-1)-0.8, A(1)= 0.2

Explicit Formula

Now, let's recall the general form of an explicit formula. A(n)=A(1)+(n-1)d In the above formula, n, d, and A(1) are the term number, the common difference, and the first term, respectively. By substituting A(1)= 0.2 and d= - 0.8 into this rule, we can create our explicit formula.
A(n)=A(1)+(n-1)d
A(n)= 0.2+(n-1)( -0.8)
We obtained the explicit formula. Explicit Formula A(n)=0.2+(n-1)(-0.8)