Exercise 52 Page 280

To find certain terms in a sequence described by an explicit formula, substitute the number of the desired term into the given formula to get the term's value. A(n)=1+(n-1)(-6)We can find the second, fourth, and eleventh terms of the sequence by substituting 2, 4, and 11 for n into the above formula.

A(n)=1+(n-1)(-6)

Substitute

n= 2

A( 2)=1+( 2-1)(-6)

SubTerm

Subtract term

A(2)=1+(1)(-6)

IdPropMult

Identity Property of Multiplication

A(2)=1+(-6)

AddNeg

a+(- b)=a-b

A(2)=1-6

SubTerm

Subtract term

A(2)=-5

Now, let's do the same thing for the fourth and eleventh terms.

n^(th) term	1+(n-1)(-6)	A(n)
2	1+( 2-1)(-6)	-5
4	1+( 4-1)(-6)	-17
11	1+( 11-1)(-6)	-59

The second, fourth, and eleventh terms are -5, -17, and -59.