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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

7. Arithmetic Sequences

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Exercise 50 Page 280

Substitute 2, 4, and 11 for n.

Second: 4
Fourth: 11
Eleventh: 35.5

Practice makes perfect

To find certain terms in a sequence described by an explicit formula, substitute the number of the desired term into the given formula to get the term's value. A(n)=0.5+(n-1)(3.5)We can find the second, fourth, and eleventh terms of the sequence by substituting 2, 4, and 11 for n into the above formula.

A(n)=0.5+(n-1)(3.5)

n= 2

A( 2)=0.5+( 2-1)(3.5)

Subtract term

A(2)=0.5+(1)(3.5)

Identity Property of Multiplication

A(2)=0.5+(3.5)

Remove parentheses

A(2)=0.5+3.5

Add terms

A(2)=4

Now, let's do the same thing for the fourth and eleventh terms.

n^(th) term	0.5+(n-1)(3.5)	A(n)
2	0.5+( 2-1)(3.5)	4
4	0.5+( 4-1)(3.5)	11
11	0.5+( 11-1)(3.5)	35.5

The second, fourth, and eleventh terms are 4, 11, and 35.5.

Subchapter links

Lesson Check p.278

Practice and Problem-Solving Exercises p.279-281

Standardized Test Prep p.281

Mixed Review p.281