Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. Arithmetic Sequences
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Exercise 55 Page 280

A sequence is arithmetic if the difference between two consecutive terms is constant.

Is the Sequence Arithmetic? Yes.
Explanation: See solution.
Recursive Formula: A(n)=A(n-1)-4, A(1)=- 3
Explicit Formula: A(n)=-3+(n-1)(- 4)

Practice makes perfect

When a sequence is arithmetic, the difference between two consecutive terms is constant. Examining our sequence we can see that this is the case. -3 +( - 4) ⟶ -7 +( - 4) ⟶ -11 +( - 4) ⟶ -15 +( - 4) ⟶ ... Since the difference between consecutive terms is constant and equal to - 4, we have an arithmetic sequence with common difference - 4. We will use this information to write both the recursive and the explicit formula.

Recursive Formula

Let's recall the general form of the recursive formula for an arithmetic sequence. A(n)=A(n-1)+d In the above formula, n is the term number and d the common difference. By substituting d= - 4 into this formula, we can create our recursive rule.

A(n)=A(n-1)+d
A(n)=A(n-1)+( -4)
A(n)=A(n-1)-4

To complete the recursive formula, we need to state the value of the first term, which in this case is A(1)= - 3. Recursive Formula A(n)=A(n-1)-4, A(1)= - 3

Explicit Formula

Now, let's recall the general form of an explicit formula. A(n)=A(1)+(n-1)d In the above formula, n, d, and A(1) are the term number, the common difference, and the first term, respectively. By substituting A(1)= - 3 and d= - 4 into this rule, we can create our explicit formula.

A(n)=A(1)+(n-1)d
A(n)= -3+(n-1)( -4)

We obtained the explicit formula. Explicit Formula A(n)=-3+(n-1)(-4)