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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

7. Arithmetic Sequences

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Exercise 49 Page 279

Substitute 2, 4, and 11 for n.

Second: 17
Fourth: 33
Eleventh: 89

Practice makes perfect

To find certain terms in a sequence described by an explicit formula, substitute the number of the desired term into the given formula to get the term's value. A(n)=9+(n-1)(8)We can find the second, fourth, and eleventh terms of the sequence by substituting 2, 4, and 11 for n into the above formula.

A(n)=9+(n-1)(8)

n= 2

A( 2)=9+( 2-1)(8)

Subtract term

A(2)=9+(1)(8)

Identity Property of Multiplication

A(2)=9+(8)

Remove parentheses

A(2)=9+8

Add terms

A(2)=17

Now, let's do the same thing for the fourth and eleventh terms.

n^(th) term	9+(n-1)(8)	A(n)
2	9+( 2-1)(8)	17
4	9+( 4-1)(8)	33
11	9+( 11-1)(8)	89

The second, fourth, and eleventh terms are 17, 33, and 89.

Subchapter links

Lesson Check p.278

Practice and Problem-Solving Exercises p.279-281

Standardized Test Prep p.281

Mixed Review p.281