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Arithmetic sequences are a foundational concept. They involve a series of numbers with a constant difference between each term, known as the common difference. Two primary rules govern these sequences: the explicit rule and the recursive rule. The explicit rule allows you to find any term in the sequence directly, while the recursive rule requires you to know the preceding term to find the next one. Understanding these rules can be incredibly useful in various real-world scenarios, such as financial planning, engineering calculations, and even in everyday problem-solving.
| | 16 Theory slides |
| | 8 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Patterns are also very common in the process of making things. Consider a car factory that bases its production of cars following a specific pattern. In their case, they have planned for the number of cars they produce to increase by the same amount each month.
Patterns like the given scenarios can be modeled using sequences. This lesson demonstrates these sequences and explores a special type called an arithmetic sequence.
A sequence is an ordered list of objects or elements called terms. The terms are often represented using a variable labeled with indices that specify the positions of the terms in the sequence.
An arithmetic sequence is a sequence that has a constant difference between consecutive terms — that is, the difference between the first and the second term is the same as the difference between the second and the third term, and so on. This difference is called the common difference and is usually denoted with d. For example, consider the sequence of all even positive integers
The following applet shows the firsts five terms of an infinite sequence. Analyze them carefully and determine whether or not the sequence is arithmetic.
Every arithmetic sequence can be described by a linear function that is defined for the set of counting numbers. This function, referred to as the explicit rule of an arithmetic sequence, follows a specific general format.
a_n = a_1 + (n-1)d
Here, a_1 is the first term and d is the common difference of the sequence. This function receives the position of a term, n, as an input and returns the value of the term in that position, a_n, as an output.
Tables can help in identifying the pattern and writing a general expression.
| n | a_n | Rewrite |
|---|---|---|
| 1 | a_1 | a_1 + 0 * d |
| 2 | a_2 | a_1 + 1 * d |
| 3 | a_3 | a_1 + 2 * d |
| 4 | a_4 | a_1 + 3 * d |
| 5 | a_5 | a_1 + 4 * d |
The coefficient of the common difference is always 1 less than the value of the position n. This makes it possible to write an explicit rule like the following formula.
a_n = a_1 + (n - 1)d
Therefore, the explicit rule for the sequence can be written by substituting the coordinate pair ( 1, a_1) into the point-slope form of a line. Point-Slope Form y - y_1 = m(x - x_1) [0.8em] Explicit Rule a_n - a_1 = d(n- 1) Finally, the explicit rule can be rewritten to the form given at the beginning of this proof. a_n - a_1 = d(n-1) ⇕ a_n = a_1 + (n-1)d
Davontay goes to a cinema to see a new movie about a kid who runs like the wind. Waiting for the movie to start, he notices something very interesting about the theater itself.
Which of the following explicit rules describes this situation and can predict the number of seats in each row?
It can be seen that the common difference d in this case is 2, and the first term a_1 is 8. Recall that the explicit rule of an arithmetic sequence is of the following form. a_n = a_1 + (n-1) d By substituting the corresponding values, the explicit rule can be found. a_n = 8 + (n-1) 2
n= 8
Subtract term
Multiply
Add terms
n= 50
Subtract term
Multiply
Add terms
Therefore, there would be 106 seats in the 50^\text{th} row.
Davontay, inspired by a movie about running, downloaded an app that keeps track of his total running distance. It even predicts his running goals. He went for a long run on his first day using it and has followed that same route ever since. One day, he opened the app, but the free trial period was over, and his data was locked!
It can be seen that in 4 days (day 23 to day 27) the total distance increased by 10 kilometers (60 to 70 kilometers). Since each day the total distance increased by d, this 10 kilometers increment should be equal to 4 d. 10 = 4 d ⇔ d = 2.5 Recall the explicit rule of an arithmetic sequence. a_n = a_1 + (n-1) d The common difference found earlier can now be substituted into the formula. a_n = a_1 + (n-1) 2.5 Next, find a_1. This can be done by evaluating the explicit rule in place of one of the known terms. As a demonstration, since it is given that a_(23) = 60, the rule can be evaluated at n=23 and solved for a_1.
n= 23
a_(23)= 60
Subtract term
Multiply
LHS-55=RHS-55
Rearrange equation
Therefore, the first term a_1 is 5. With this information, the explicit rule can be completed. a_n = 5 + (n-1)2.5
a_n=5+(n-1)2.5
By substituting 150 for a_n an equation for n will be obtained. The solution to the equation is the number of the day that corresponds to this distance.a_n= 150
LHS-5=RHS-5
.LHS /2.5.=.RHS /2.5.
LHS+1=RHS+1
Rearrange equation
Therefore, Davontay needs 59 days to reach his personal goal of running 150 kilometers in total. He did all of this without needing to pay for the pro version, thanks to the help of arithmetic sequences. Maybe now he can go run like the wind!
The following applet shows two of the first five terms of an infinite arithmetic sequence. Analyze the sequence carefully and determine which of the three options is the correct explicit rule of the sequence.
The following applet shows the first five terms of an infinite arithmetic sequence. Determine the explicit rule of the sequence and use it to find the indicated term.
It has been shown how an explicit rule describes an arithmetic sequence. This representation uses a formula that receives the term position as the input and returns the term's value as the output. However, an arithmetic sequence can also be described by using a recursive rule.
A recursive rule of an arithmetic sequence is a pair comprised of a recursive equation telling how the term a_n is related to its preceding term a_(n-1) and the initial term of the sequence a_1.
a_1, a_n = a_(n-1) + d
In the equation above, d represents the common difference. The following applet gives an example recursive rule for an arithmetic sequence. It shows how the rule can be used to determine the first five terms of the sequence.
Now it will be explained, step by step, how to write the recursive rule for an arithmetic sequence and how to use it to find an unknown term's value.
The recursive rule of an arithmetic sequence gives the first term of the sequence and a recursive equation.
a_1, a_n = a_(n-1) +d
Consider an example arithmetic sequence. cc a_1 & a_2 & a_3 & a_4 & 5, & 8, & 11, & 14, & ... To write the recursive rule there are three steps to follow.
If the sequence was known to be arithmetic but no consecutive terms were known, the common difference could still be found. In general, it is enough to know two terms of the arithmetic sequence and their positions. For example, consider that only a_2 and a_4 were known. cc a_1 & a_2 & a_3 & a_4 & ?, & 8, & ?, & 14, & ... Recall the general form of an arithmetic sequence.
Since each term increases by d, a_2 is equal to a_1+d and a_4 is equal to a_1+3d. a_4 = a_1+3d &⇒ 14 = a_1+3d a_2 = a_1+ d &⇒ 8 = a_1+ d By subtracting the corresponding sides of the resulting equations, a single equation, which can be solved for d, is obtained.
Reconsider the case where only a_2 and a_4 are known. Two equations were obtained. 14 &= a_1+3 d 8 &= a_1+ d Since it is now known that d= 3, this value can be substituted in any of the equations to find a_1. This will be illustrated using the latter equation. 8 = a_1+ 3 ⇒ a_1 = 5
Davontay finds himself looking at his phone app too often when running. He has an idea! He will make patterns using heavy rocks at each kilometer mark along his running route so he does not have to check his phone to know what point his on the run.
Davontay wants to make a fourth figure following the same pattern. Before setting out to collect more heavy rocks, he wants to model the pattern to save time and energy.
Now, to prove that the sequence obtained this way is arithmetic, the difference between consecutive terms will be calculated.
Since the difference is constant, the sequence is arithmetic. Recall that the recursive equation for an arithmetic sequence is of the following form. a_1, a_n = a_(n-1) + d In this equation, d represents the common difference of the sequence which was already found to be d = 4. This value will now be substituted into the general recursive equation. a_n = a_(n-1) + d ⇓ a_n = a_(n-1) + 4 To finish writing the recursive rule, it is needed to specify the first term of the sequence a_1. This can be identified in the previous diagram.
Using this information the explicit rule will now be completed. a_1 = 8, a_n = a_(n-1) + 4
n= 4
Subtract term
a_3= 13
Add terms
Davontay needs to collect 17 rocks for the next figure to place along his running route.
Davontay is celebrating the completion of reaching his running goal. His family and friends throw him a party. They play a raffle game and he wins $50! He decides not to spend this money, instead, he will save it and put it in a piggy bank.
Davontay is planning to add $5 every week. Thanks to the math he has practiced, he knows that the following recursive rule models his savings. a_1=50, a_n = a_(n-1)+5 In this expression, a_n represents the total savings after the n^\text{th} week.
a_n = 100 + (n-1)10 In this equation a_n represents the total savings after the n^\text{th} week. Davontay would prefer to have a recursive rule since he thinks that it makes the weekly savings calculation easier. Help Davontay find the corresponding recursive rule.
Savings After Week 2: $55
Savings After Week 3: $60
n= 2
Subtract term
a_1= 50
Add terms
The total savings after week 2 is $55. The same procedure can be repeated for n=3 and n=4. It is important to follow this procedure in order, since any term value can only be figured out if the previous term is known — just like the value of a_1 was needed to find the value of a_2. The following table shows a summary of the calculations.
| a_1 =50, a_n=a_(n-1) +5 | ||
|---|---|---|
| Position | Substitute | Simplify |
| n=1 | a_1 =50 | a_1 = 50 |
| n=2 | a_2 = a_1 + 5 ⇓ a_2 = 50 + 5 | a_2 = 55 |
| n=3 | a_3 = a_2 + 5 ⇓ a_3 = 55 + 5 | a_3 = 60 |
| n=4 | a_4 = a_3 + 5 ⇓ a_4 = 60 + 5 | a_4 = 65 |
General Recursive Rule a_1, a_n = a_(n-1)+ d [1em] Given Recursive Rule a_1= 50, a_n = a_(n-1)+ 5 It is now understood that a_1 = 50 and d= 5. Next, use the general form of an explicit rule and substitute the previously identified values. a_n = a_1 + (n-1) d ⇓ a_n = 50 + (n-1) 5 Finally to find the value after a years worth of savings — 52 weeks — the explicit rule will be evaluated using n=52.
n= 52
Subtract term
Multiply
Add terms
Davontay will save $305 after one year.
General Explicit Rule a_n = a_1 + (n-1) d [1em] Given Explicit Rule a_n = 100 + (n-1) 10 As seen, a_1= 100 and d= 10. Next, recall the general form of a recursive rule and substitute the values for a_1 and d. a_1, a_n = a_(n-1) + d ⇓ a_1 = 100, a_n = a_(n-1) + 10
Find the corresponding explicit rule for the recursive rule shown.
It was previously shown that the terms' values of an arithmetic sequence change by a constant amount. Because of that consistent change, every arithmetic sequence has an associated linear relationship where the common difference is the slope of its associated line. To illustrate this, consider the following arithmetic sequence.
The sequence has a common difference of 4. Its initial term is a_1= 2. Using this information, its explicit rule can be stated. a_n = a_1 + (n-1) d ↓ a_n = 2 + (n-1) 4 This rule can be simplified by distributing and subtracting 4, in that order.
The sequence can be represented graphically using this expression. Treat the terms position n as the independent variable, and treat the terms value a_n as the dependent one. See how the graph of a sequence compares to that of the linear function f(x) = 4x - 2. Note how the common difference of the sequence relates to the slope of the line.Now that sequences have been introduced and understood, the pattern presented at the beginning of the lesson can be modeled using a sequence. Then, the number of circles for Figure 20 can be calculated. Interact with the applet once more, predicting the next figure.
Since the number of circles used increases by a constant amount, this sequence is arithmetic.
To find the number of circles appearing in Figure 20, find the explicit rule for this arithmetic sequence. The explicit rule of an arithmetic sequence has the following general form.
a_n = a_1 + (n-1)d
In this equation, a_1 is the first term of the sequence and d is the common difference. Both can be identified from the previous diagram.
The initial term a_1= 4 and d= 3. These values can be substituted in the general explicit rule form.
a_n = a_1 + (n-1) d ⇓ a_n = 4 + (n-1) 3
Finally, to find the number of circles in Figure 20, the explicit rule will be evaluated at n=20.
n= 20
Subtract term
Multiply
Add terms
Figure 20 will have 61 circles.
Let's remember the formula for the n^\text{th} term of an arithmetic sequence. a_n=a_1+(n-1)d In this equation, a_1 is the first term of a sequence and d is the common difference. Let's now use the graph to list the first four terms of the sequence. Notice that the horizontal axis shows us n, the term number. The vertical axis shows us a_n, the value of the term. \begin{aligned} &\bm{1}^\textbf{st}\textbf{ term:}&1 \\ &\bm{2}^\textbf{nd}\textbf{ term:}&5 \\ &\bm{3}^\textbf{rd}\textbf{ term:}&9 \\ &\bm{4}^\textbf{th}\textbf{ term:}&13 \end{aligned} Having the first term 1 from the graph, we will now find d by calculating the difference between any two consecutive terms. Here we will use the second and third terms. a_3-a_2=d ⇒ 9-5=4 Now we can substitute these values into the formula and simplify.
The formula for the n^\text{th} term is a_n=4n-3.
Let's recall the slope-intercept form of a linear equation.
y=mx+b
Here, m is the slope and b is the y-intercept. To find the slope, we can take two points from the graph and substitute them into the Slope Formula. Let's randomly use (1,1) and (3,9).
Let's now calculate b by substituting m and the point (2,5) into the general equation. Note that we can use any points for this — we chose this point arbitrarily.
Now that we know both m and b, we can write the formula for the function. y=4x-3
The fifth term of an arithmetic sequence is -2. If the common difference is 5, what is the first term?
Let's visualize the information we have been given. a_1 +5 → a_2 +5 → a_3 +5 → a_4 +5 → -2 To get to the fifth term, we have to add 5 four times to a_1. a_1+5+5+5+5=-2 ⇕ a_1+4* 5=-2 Now we have an equation for a_1 that we can solve.
The first term is -22.
The common difference of an arithmetic sequence is 3. If a_(15)=33, what is the value of a_1?
Let's use the formula for the n^\text{th} term of an arithmetic sequence. a_n=a_1+( n-1) d Since we know the common difference d= 3 and a_(15)= 33, we can substitute 3 for d, 15 for n, and 33 for a_n. 33=a_1+( 15-1) 3 Since a_1 is the only unknown value left, we can solve the equation for it.
The first term is -9.