McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
6. The Law of Sines and Law of Cosines
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Exercise 54 Page 678

Recall the Law of Sines.

Neither of them is correct. See solution.

Practice makes perfect

We are given that Colleen and Mike are planning a party, and Colleen wants to sew decorations in the shape of isosceles triangles with angle measures of 64^(∘) at the base and side lengths of 5 inches. Let's sketch a diagram describing this situation.

To evaluate the perimeter of one triangle, we need to know all the side lengths. Let x represent the length of the base of this triangle. First, we can evaluate the measure of the third angle, let's call it y, by the Triangle Angle Sum Theorem.
y+ 64^(∘)+ 64^(∘)=180^(∘)
y+128^(∘)=180^(∘)
y=52^(∘)

Let's add this information to our diagram.

Next, let's recall the Law of Sines. If △ ABC has lengths of a, b, and c and angle measures of A, B, and C, then we can write that the ratios of the sine of an angle to the side opposite this angle are equal.

Using this law, we can create a proportion for x. sin 64^(∘)/5=sin 52^(∘)/x We can solve this equation using cross multiplication.
sin 64^(∘)/5=sin 52^(∘)/x
xsin 64^(∘)=5sin52^(∘)
x=5sin 52^(∘)/sin 64^(∘)
x=4.3837...
x≈ 4.4
The length of the base of this triangle is approximately 4.4.

As we know all the side lengths, we can evaluate the perimeter of the triangle. P= 5+ 5+4.4=14.4 The perimeter of one triangle is approximately 14.4. This means that neither Colleen nor Mike is correct.