Exercise 14 Page 675

For any △ ABC, let the lengths of the sides opposite angles A, B, and C be a, b, and c, respectively.

sin A/a=sin B/b=sin C/c Let's use this law to find the value of x. Consider the given triangle.

We know that the length of a side is 8 and that the measure of its opposite angle is 73. We want to find the length of the side that is opposite to the angle whose measure is 67. We can use the Law of Sines again! sin 73/8=sin 67/x Let's solve the above equation for x using the Cross Product Property.

sin 73/8=sin 67/x

▼

Solve for x

CrossMult

Cross multiply

sin 73* x=sin 67* 8

DivEqn

.LHS /sin 73.=.RHS /sin 73.

x=sin 67* 8/sin 73

UseCalc

Use a calculator

x=7.700514...

RoundDec

Round to 1 decimal place(s)

x≈ 7.7