Exercise 12 Page 675

For any △ ABC, let the lengths of the sides opposite angles A, B, and C be a, b, and c, respectively.

sin A/a=sin B/b=sin C/c Let's use this law to find the value of x. Consider the given triangle.

We know that the length of a side is 24 and that the measure of its opposite angle is 30. We want to find the length of the side that is opposite to the angle whose measure is 47. We can use the Law of Sines again! sin 30/24=sin 47/x Let's solve the above equation for x using the Cross Product Property.

sin 30/24=sin 47/x

▼

Solve for x

CrossMult

Cross multiply

sin 30* x=sin 47* 24

DivEqn

.LHS /sin 30.=.RHS /sin 30.

x=sin 47* 24/sin 30

UseCalc

Use a calculator

x=35.104977...

RoundDec

Round to 1 decimal place(s)

x≈ 35.1