Exercise 15 Page 675

For any △ ABC, let the lengths of the sides opposite angles A, B, and C be a, b, and c, respectively.

sin A/a=sin B/b=sin C/c Let's use this law to find the value of x. Consider the given triangle.

We know that the length of a side is 11 and that the measure of its opposite angle is 27. We want to find the length of the side that is opposite to the angle whose measure is 110. We can use the Law of Sines again! sin 27/11=sin 110/x Let's solve the above equation for x using the Cross Product Property.

sin 27/11=sin 110/x

▼

Solve for x

CrossMult

Cross multiply

sin 27* x=sin 110* 11

DivEqn

.LHS /sin 27.=.RHS /sin 27.

x=sin 110* 11/sin 27

UseCalc

Use a calculator

x=22.768359...

RoundDec

Round to 1 decimal place(s)

x≈ 22.8