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Use the Law of Sines and relate the sine of each angle to the length of the opposite side.
m ∠G = 75
CB≈ 9.8
BA≈ 7.5
Let's begin by drawing â–³ ABC and labeling the lengths of the sides. We will also color code the opposite angles, sides, and the vertices in the given triangle. It will help us use the Law of Sines later.
Let's first find the measure of the third interior angle which is m∠G, and then the measures of the missing side lengths one at a time.
To find m ∠A we can use the Triangle Angle Sum Theorem. This tells us that the measures of the angles in a triangle add up to 180.
Note that we know the m ∠B and the length of the side which is opposite to this angle. We want to find the length of the side, a, that is opposite to the ∠A. Therefore, we can use the Law of Sines. sin B/b =sin A/a Let's substitute b= 15, m ∠B= 119, and m ∠A= 35 to isolate a.
We found that the length of the side CB is about 9.8 units.
Finally, to find BA we will use the Law of Sines one more time. sin B/b =sin C/c Let's substitute b= 15, m ∠B= 119, and m ∠C= 26 to isolate c.
We found that the length of the side BA is about 7.5 units.
With all of the angle measures and side lengths, we can complete our diagram.