For any â–³ ABC, let the lengths of the sides opposite angles A, B, and C be a, b, and c, respectively.
The Law of Sines relates the sine of each angle to the length of the opposite side.
sin A/a=sin B/b=sin C/c
Let's use this law to find the value of x.
Consider the given triangle.
We know that the length of a side is 5 and that the measure of its opposite angle is 68. We want to find the length of the side that is opposite to the angle whose measure is 50. We can use the Law of Sines again!
sin 68/5=sin 50/x
Let's solve the above equation for x using the Cross Product Property.
