body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

1. Solving Simple Equations

Continue to next subchapter

Exercise 34 Page 9

Use the Multiplication Property of Equality.

y=-10

Practice makes perfect

To solve the given equation for y, we need to isolate it by multiplying both sides of the equation by - 52. We want to multiply by - 52 because it is the reciprocal of - 25. This is allowed by the Multiplication Property of Equality.

-2/5y=4

-5/2* LHS =-5/2* RHS

-5/2(-2/5y)=-5/2* 4

MultNegNegOnePar

- a(- b)=a* b

5/2*(2/5y)=-5/2* 4

AssociativePropMult

Associative Property of Multiplication

(5/2*2/5)y=-5/2* 4

MultFracByInverse

a/b* b/a=1

1* y =-5/2* 4

Identity Property of Multiplication

y=-5/2* 4

MoveRightFacToNum

a/c* b = a* b/c

y=-5* 4/2

Multiply

y=-20/2

Calculate quotient

y=- 10

We will check our solution by substituting this result back into the original equation and simplifying. If doing so results in an identity, our solution is correct.

-2/5y=4

y= -10

-2/5( -10)? =4

MultNegNegOnePar

- a(- b)=a* b

2/5* 10? =4

MoveRightFacToNum

a/c* b = a* b/c

2* 10/5? =4

Multiply

20/5? =4

Calculate quotient

4=4 ✓

Since substituting y=-10 resulted in an identity, our solution is correct.

Subchapter links

Communicate Your Answer p.3

Monitoring Progress p.4-7

Exercises p.8-10