Exercise 23 Page 8

Use the Multiplication Property of Equality.

p=15, see solution.

Practice makes perfect

To solve the given equation for p, we need to isolate it by multiplying both sides of the equation by 5. We want to multiply by 5 because division and multiplication are inverse operations — they cancel each other out. This is allowed by the Multiplication Property of Equality.

p÷5=3

WriteAsFrac

Write as a fraction

p/5=3

MultEqn

LHS * 5=RHS* 5

p/5*5=3*5

FracMultDenomToNumber

a/5* 5 = a

p=3*5

Multiply

p=15

We will check our solution by substituting this result back into the original equation and simplifying. If doing so results in an identity, our solution is correct.

p÷5=3

Substitute

p= 15

15÷5? =3

WriteAsFrac

Write as a fraction

15/5? =3

CalcQuot

Calculate quotient

3=3 ✓

Since substituting p=15 resulted in an identity, our solution is correct.