Exercise 48 Page 9

Isolate x on one of the sides and, if needed, substitute c with increasing values and see what happens.

Equation	Value of x
x-c=0	Increases
cx=1	Decreases
cx=c	Stays the same
x/c=1	Increases

Practice makes perfect

Let's solve each equation for x and then substitute increasing values of c if it is not obvious how x will behave.

Equation 1

Let's solve for x.

x-c=0

AddEqn

LHS+c=RHS+c

x=c

In this equation, x is equal to c, so as c increases, x also increases.

Equation 2

Let's solve for x.

cx=1

DivEqn

.LHS /c.=.RHS /c.

x=1/c

By substituting c with increasing numbers, we can determine what happens to the value of x.

c	1/c	=
1	1/1	1
2	1/2	0.5
3	1/3	0.333333...

From the table, we see that as c increases, x decreases.

Equation 3

Let's solve for x.

cx=c

DivEqn

.LHS /c.=.RHS /c.

x=c/c

QuotOne

a/a=1

x=1

Since x equals 1, it does not depend on the value of c. In other words, it stays the same.

Equation 4

Let's solve for x.

x/c=1

MultEqn

LHS * c=RHS* c

x=c

Again, x equals c which means that as c increases, x increases too.

Subchapter links

Communicate Your Answer p.3

Monitoring Progress p.4-7

Exercises p.8-10

Exercise 48 Page 9

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Equation 1

Equation 2

Equation 3

Equation 4