Exercise 8 Page 8

To solve the given equation for s, we need to isolate it by adding 2 to both sides of the equation. We want to add 2 because subtraction and addition are inverse operations — they cancel each other out. This is allowed by the Addition Property of Equality.

s-2=1

AddEqn

LHS+2=RHS+2

s-2+2=1+2

AddTerms

Add terms

s=3

We will check our solution by substituting this result back into the original equation and simplifying. If doing so results in an identity, our solution is correct.

s-2=1

Substitute

s= 3

3-2? =1

SubTerm

Subtract term

1=1 ✓

Since substituting s=3 resulted in an identity, our solution is correct.