Exercise 1 Page 674

For any △ ABC, let the lengths of the sides opposite angles A, B, and C be a, b, and c, respectively.

sin A/a=sin B/b=sin C/c Let's use this law to find the value of x. Consider the given triangle.

We know that the length of a side is 9 and that the measure of its opposite angle is 58. We want to find the length of the side that is opposite to the angle whose measure is 35. We can use the Law of Sines again! sin 58/9=sin 35/x Let's solve the above equation for x using the Cross Product Property.

sin 58/9=sin 35/x

▼

Solve for x

CrossMult

Cross multiply

sin 58* x=sin 35* 9

DivEqn

.LHS /sin 58.=.RHS /sin 58.

x=sin 35* 9/sin 58

UseCalc

Use a calculator

x=6.087140...

RoundDec

Round to 1 decimal place(s)

x≈ 6.1