Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Standard Form
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Exercise 63 Page 328

Practice makes perfect
a Let x represent the ticket prices of students and y represent the ticket prices of adults. We think that 200 students and 150 adults will attend. If we want to raise $1000 and the talent show costs $200, we can write the equation as the following.
Verbal Expression Algebraic Expression
Revenue from students 200* x
Revenue from adults 150* y
Find the total revenue 200* x+ 150* y
Add the needed money and the cost of talent show $1000+ $200
Form the equation 200* x+ 150* y= $1200

Thus, the equation is the following. 200x+ 150y= 1200

b Now we will find the interception points of the equation to graph it. Let's start with the x-intercept. In order to find the x-intercept, we will substitute 0 for y and solve the equation for x.
200x+150y=1200
200x+150( 0)=1200
200x=1200
x=6
The x-intercept is the point (6,0). We can find the y-intercept by following the same steps.
200x+150y=1200
200( 0)+150y=1200
150y=1200
y=8
Thus, the y-intercept is the point (0,8). Next, we will plot the interception points and graph the equation by connecting them.

As a final step, we will choose three points that lie on the line to write 3 possible combinations of ticket prices.

Let's list the three possible combinations in a table so we can see them better.

Ticket price of students Ticket price of adults
$1.50 $6
$2.25 $5
$3 $4