Sign In
Equation: 200x+150y=1200
Graph:
Possible Combinations:
| Ticket price of students | Ticket price of adults |
|---|---|
| $1.50 | $6 |
| $2.25 | $5 |
| $3 | $4 |
Let x represent the ticket prices of students and y represent the ticket prices of adults. We think that 200 students and 150 adults will attend. If we want to raise $1000 and the talent show costs $200, we can write the equation as the following.
| Verbal Expression | Algebraic Expression |
|---|---|
| Revenue from students | 200* x |
| Revenue from adults | 150* y |
| Find the total revenue | 200* x+ 150* y |
| Add the needed money and the cost of talent show | $1000+ $200 |
| Form the equation | 200* x+ 150* y= $1200 |
Thus, the equation is the following. 200x+ 150y= 1200
Now we will find the interception points of the equation to graph it. Let's start with the x-intercept. In order to find the x-intercept, we will substitute 0 for y and solve the equation for x.
y= 0
Zero Property of Multiplication
.LHS /200.=.RHS /200.
The x-intercept is the point (6,0). We can find the y-intercept by following the same steps.
x= 0
Zero Property of Multiplication
.LHS /150.=.RHS /150.
Thus, the y-intercept is the point (0,8). Next, we will plot the interception points and graph the equation by connecting them.
As a final step, we will choose three points that lie on the line to write 3 possible combinations of ticket prices.
Let's list the three possible combinations in a table so we can see them better.
| Ticket price of students | Ticket price of adults |
|---|---|
| $1.50 | $6 |
| $2.25 | $5 |
| $3 | $4 |