Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Standard Form
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Exercise 54 Page 327

Try using the Slope Formula and point-slope form to write an equation before solving for the x- and y-intercepts.

x-intercept: (- 535,0)
y-intercept: (0, 533)

Practice makes perfect

To determine the x- and y-intercepts of a line, we need to substitute 0 for one variable, solve, then repeat for the other variable. In this case, we haven't been given an equation, so we will need to use the given points to write one.

Writing the Equation

The quickest way to write an equation, given two points, is by using the point-slope form. An equation in point-slope form follows a specific format. y- y_1= m(x- x_1) In this form, m is the slope and the point ( x_1, y_1) lies on the graph of the line. To create our equation, we can use either of the given points for x_1 and y_1 as well as the slope. To calculate the slope, we will use the Slope Formula.
m=y_2-y_1/x_2-x_1
m=11- 6/- 4- (-7)
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Simplify RHS
m=11-6/-4+7
m=5/3
Using the point ( -7, 6) as our point and the slope 53, we have everything needed to form a point-slope form equation. y- 6= 5/3(x-( -7)) ⇕ y-6=5/3(x+7) Note that there are infinitely many correct ways to write this equation in point-slope form, as long as we use a point that lies on the line.

Finding the x-intercept

Think of the point where the graph of an equation crosses the x-axis. The y-value of that ( x, y) coordinate pair is 0, and the x-value is the x-intercept. To find the x-intercept of the equation, we should substitute 0 for y and solve for x.
y-6=5/3(x+7)
0-6=5/3(x+7)
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Solve for x
-6=5/3(x+7)
-6=5/3x+5/3(7)
-6=5/3x+35/3
-18=5x+35
-53=5x
-53/5=x
-53/5=x
x=-53/5
An x-intercept of - 535 means that the graph passes through the x-axis at the point ( - 535,0).

Finding the y-intercept

Let's use the same concept to find the y-intercept. Consider the point where the graph of the equation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, substituting 0 for x will give us the y-intercept.
y-6=5/3(x+7)
y-6=5/3( 0+7)
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Solve for y
y-6=5/3(7)
y-6=35/3
y=35/3+6
y=35/3+18/3
y=53/3
A y-intercept of 533 means that the graph passes through the y-axis at the point (0, 533).