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Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
- 1.2, 5.2
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇕ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side and then simplify as much as possible.
LHS-12=RHS-12
Factor out 2
.LHS /2.=.RHS /2.
Now, we can identify the values of a, b, and c. x^2 - 4x - 6 ⇕ 1x^2+( - 4)x+( - 6)=0 We see that a= 1, b= - 4, and c= - 6. Let's substitute these values into the Quadratic Formula.
Substitute values
- (- a)=a
Calculate power
a * 1=a
- a(- b)=a* b
Add terms
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out 2
Cancel out common factors
The solutions for this equation are x=2 ± sqrt(10). Let's separate them into the positive and negative cases.
| x=2 ± sqrt(10) | |
|---|---|
| x_1=2 - sqrt(10) | x_2=2 + sqrt(10) |
| x_1 ≈ - 1.2 | x_2 ≈ 5.2 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1 ≈ - 1.2 and x_2 ≈ 5.2.