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Make sure you write all the terms on the left-hand side of the equation before using the Quadratic Formula.
2.2, 0.6
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇕ x=- b± sqrt(b^2-4 a c)/2 a
Let's start by rewriting the equation so all of the terms are on the left-hand side.
Substitute values
- (- a)=a
Calculate power
Multiply
- a(- b)=a* b
Add terms
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Calculate root
Factor out 2
Cancel out common factors
The solutions for this equation are x= 4± sqrt(46)5. Let's separate them into the positive and negative cases.
| x=4± sqrt(46)/5 | |
|---|---|
| x_1=4 + sqrt(46)/5 | x_2=4 - sqrt(46)/5 |
| x_1 ≈ 2.2 | x_2 ≈ - 0.6 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1 ≈ 2.2 and x_2 ≈ - 0.6.