McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Solving Quadratic Equations by Using the Quadratic Formula
Continue to next subchapter

Exercise 17 Page 137

You cannot calculate the root of a negative number.

No real solution.

Practice makes perfect
We will use the Quadratic Formula to solve the given quadratic equation. ax^2+ bx+ c=0 ⇕ x=- b± sqrt(b^2-4 a c)/2 aWe first need to identify the values of a, b, and c. x^2 + 16 = 0 ⇕ 1x^2+ 0x+ 16=0 We see that a= 1, b= 0, and c= 16. Let's substitute these values into the Quadratic Formula.
x=- b±sqrt(b^2-4ac)/2a
x=- 0±sqrt(0^2-4( 1)( 16))/2( 1)
x=- 0±sqrt(-4(1)(16))/2(1)
x=- 0±sqrt(- 64)/2
Since we cannot calculate the root of a negative number, there are no real solutions of the given equation.