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Be careful with the signs when substituting in the Quadratic Formula.
8 and 2
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
To do so, we first need to identify the values of a, b, and c.
Substitute values
The solutions for this equation are x= 10± 62. Let's separate them into the positive and negative cases.
| x=10± 6/2 | |
|---|---|
| x_1=10+ 6/2 | x_2=10- 6/2 |
| x_1=16/2 | x_2=4/2 |
| x_1=8 | x_2=2 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1=8 and x_2=2.