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McGraw Hill Integrated II, 2012 View details

5. Solving Quadratic Equations by Using the Quadratic Formula

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Exercise 4 Page 137

Make sure you write all the terms on the left-hand side of the equation before using the Quadratic Formula.

2.3, - 7.3

Practice makes perfect

We will use the Quadratic Formula to solve the given quadratic equation. ax^2+ bx+ c=0 ⇕ x=- b± sqrt(b^2-4 a c)/2 a Let's start by rewriting the equation so all of the terms are on the left-hand side. x^2 + 3x = 12 ⇔ x^2 + 3x - 12 = 0 Now, we can identify the values of a, b, and c. x^2 + 3x - 12 = 0 ⇕ 1x^2+ 3x+( - 12)=0 We see that a= 1, b= 3, and c= - 12. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a

SubstituteValues

Substitute values

x=- 3±sqrt(3^2-4( 1)( - 12))/2( 1)

▼

Solve for x and Simplify

CalcPow

Calculate power

x=- 3±sqrt(9-4(1)(- 12))/2(1)

MultByOne

a * 1=a

x=- 3±sqrt(9-4(- 12))/2