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Review the four methods of solving quadratic equations: completing the square, graphing, factoring, and using the discriminant.
See solution.
We will compare and contrast the four strategies for solving quadratic equations: completing the square, graphing, factoring, and using the discriminant. It will be easier to visualize these methods if we choose a quadratic equation to model them with, so let's use the following. x^2-5x-7=0
b= - 5
(a/b)^m=a^m/b^m
(- a)^2=a^2
Calculate power
LHS+25/4=RHS+25/4
Rewrite 5 as 2*5/2
Rewrite 25/4 as (5/2)^2
a^2-2ab+b^2=(a-b)^2
Therefore, the roots of the equation x^2-5x-7=0 are approximately - 1.1 and 6.1. Note that by this method we are not able to find the exact solutions and usually we will spend a lot of time plotting the parabola in a coordinate system.
To solve the given equation by factoring, we will start by identifying the values of a, b, and c. x^2-5-7x=0 ⇕ 1x^2+( - 5)x+( - 7)=0 We have a quadratic equation with a= 1, b= - 5, and c= - 7. To factor the left-hand side we need to find a factor pair of 1 * ( - 7)=- 7 whose sum is - 5. Since - 7 is a negative number, we will only consider factors with opposite signs — one positive and one negative — so that their product is negative.
| Factor Pair | Product of Factors | Sum of Factors |
|---|---|---|
| 1 and - 7 | ^(1* (- 7)) - 7 | 1+(- 7) - 6 |
| - 1 and 7 | ^(- 1* 7) - 7 | - 1+7 6 |
Unfortunately, we did not find the integers whose product is - 7 and whose sum is - 5. Therefore, we cannot continue with this strategy. Factoring does not always work — especially when the roots are not rational numbers, like in our case. Note that if the coefficient c was a big number we must do a lot of calculations.
Substitute values
- (- a)=a
Calculate power
Multiply
- a(- b)=a* b
Add terms
| x=5± sqrt(53)/2 | |
|---|---|
| x_1=5+sqrt(53)/2 | x_2=5-sqrt(53)/2 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1= 5+sqrt(53)2 and x_2= 5-sqrt(53)2. Note that this method always gives us the exact solutions.
Now we will describe the advantages and disadvantages of each method. Unfortunately, not all the methods are equivalent.
| Method | Type | Exact | Fast |
|---|---|---|---|
| Completing the Square | Algebraic | Yes | No |
| Graphing | Geometric | No | No |
| Factoring | Algebraic | No | No |
| Distriminant | Algebraic | Yes | Yes |
In general, using discriminant is the best. It is usually the fastest and always exact.